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Last updated on October 6, 2025
The derivative of e² is a constant, as e² is a constant value itself. Derivatives help us calculate changes in various scenarios. We will now discuss the derivative of e² in detail.
The derivative of e² is straightforward because e² is a constant. It is commonly represented as d/dx (e²) or (e²)'. Since e² is a constant, its derivative is zero.
The key concepts are mentioned below:
Exponential Function: The function ex is the exponential function, but e² is a constant value.
Constant Rule: The derivative of any constant is zero.
The derivative of e² can be denoted as d/dx (e²) or (e²)'. The formula we use to differentiate e² is: d/dx (e²) = 0 The formula applies to all x, as e² is a constant and does not depend on x.
We can derive the derivative of e² using the basic rules of differentiation. Since e² is a constant, we use the constant rule. The steps are as follows:
Using the Constant Rule The derivative of a constant is always zero.
To find the derivative of e², consider f(x) = e². Its derivative can be expressed as f'(x) = 0.
Hence, the derivative of e² is 0.
When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. For a constant like e², all higher-order derivatives are also zero.
To understand them better, think of a car where the speed (first derivative) and the rate of speed change (second derivative) are both zero if the car is at rest.
For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point. The second derivative is derived from the first derivative, which is denoted using f′′(x).
Similarly, the third derivative, f′′′(x), is the result of the second derivative, and this pattern continues.
For the nth Derivative of e², we generally use fⁿ(x) for the nth derivative of a function f(x), which remains zero for e².
Since e² is a constant, its derivative is always zero, regardless of the value of x. There are no special cases where the derivative changes.
Students frequently make mistakes when differentiating constants like e². These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:
Calculate the derivative of 3e² + 5x.
Here, we have f(x) = 3e² + 5x. The derivative of a constant term like 3e² is zero.
The derivative of 5x is 5. Therefore, f'(x) = 0 + 5 = 5.
We find the derivative of the given function by recognizing that 3e² is a constant, so its derivative is zero.
We then differentiate 5x as usual to get the final result.
A company finds that its profit, P, is given by P = 200e² + 10x dollars, where x is the number of units sold. What is the rate of change of profit with respect to units sold?
We have P = 200e² + 10x. The derivative of 200e² is zero, as it is a constant.
The derivative of 10x is 10.
Hence, the rate of change of profit with respect to units sold is 10 dollars per unit.
We differentiate the profit function with respect to x, recognizing that the term involving e² is constant and contributes zero to the rate of change.
Derive the second derivative of the function f(x) = e² + x².
The first step is to find the first derivative, f'(x) = 0 + 2x = 2x.
Now we will differentiate f'(x) to get the second derivative: f''(x) = d/dx [2x] = 2.
Therefore, the second derivative of the function f(x) = e² + x² is 2.
We find the first derivative by recognizing the constant term and differentiating x². We then differentiate the result to get the second derivative.
Prove: d/dx (e²x) = e².
Consider y = e²x.
To differentiate, we use the constant multiple rule:dy/dx = e² d/dx [x].
Since the derivative of x is 1, dy/dx = e²(1) = e².
In this step-by-step process, we used the constant multiple rule to differentiate the equation, recognizing that e² is a constant multiplier.
Solve: d/dx (e²/x).
To differentiate the function, we use the quotient rule: d/dx (e²/x) = (d/dx (e²) · x - e² · d/dx(x))/x².
Since d/dx (e²) = 0, = (0 · x - e² · 1)/x² = -e²/x².
Therefore, d/dx (e²/x) = -e²/x².
In this process, we differentiate the given function using the quotient rule. Recognizing the derivative of the constant e² is zero simplifies the calculation.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
: He loves to play the quiz with kids through algebra to make kids love it.